Question

Let f(x) =4x-1 and g(x) = 2x^2 + 3
(fg)(x) , f/g(x), g/f(x)

Answer 1

(fg)(x)
multiply both function

Answer 2

\[\huge\rm (fg)(x) = (4x-1)(2x^2+3)\]
apply foil method :-)

Answer 3

so 8x2 + 12 - 2x2 - 3? @Nnesha

Answer 4

when you multiply variables you should add their exponent
so remember x <----there is invisible exponent which is ?

Answer 5

\[\huge\rm x \times x^2 = x^?\]

Answer 6

1... so it should be 8x3?

Answer 7

yep!

Answer 8

now do you just simplify and thats your answer?

Answer 9

look over ur answer one more time
4x times 3 = ?? :-)

Answer 10

12x whoops

Answer 11

so 8x3 + 12x - 2x2 - 3

Answer 12

yep :-)
so \[\huge\rm 8x^3 +12x -2x^2 -3\] :-)

Answer 13

so we combine and thats the final answer ??

Answer 14

can you combine anything ??
are there any like terms to combine ?? :-)

Answer 15

well not all the x's are the same.. so maybe not

Answer 16

yes so that's it :-)

Answer 17

hm. seems simple enough

Answer 18

yeah :-)

Answer 19

can you help with just one more that is a bit harder

Answer 20

sure !
what about f/g and g/f can you divide that ?? or do you need help ?

Answer 21

oh i completely forgot about those! okay well i know you start off with
4x - 1/2x2 + 3 and 2x2+3/4x-1 but I'm not sure where to go from there

Answer 22

okay let's do first one \[\huge\rm \frac{ 4x-1 }{ 2x^2 +3 }\]
can you factor top or bottom part ?

Answer 23

i don't think so... @Nnesha

Answer 24

yes there isn't any common factor so done!

Answer 25

\[\huge\rm \frac{ 2x^2+3 }{ 4x -1 }\]
hmm for this one u can use long division ?

Answer 26

have u learned "long division " topic

Answer 27

??*