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Algebra 9 Online
OpenStudy (anonymous):

I need HELP!!!! Help meee!

OpenStudy (anonymous):

OpenStudy (anonymous):

@amistre64 PLease help!

OpenStudy (amistre64):

how is that ever exponential?

OpenStudy (amistre64):

and without any clear points to evaluate the curve on ... how do they expect you to make such an accurate approximation?

OpenStudy (anonymous):

LOL, and can you believe this is 9th grade math? Wait so you don't think it exponential?

OpenStudy (amistre64):

|dw:1430352553125:dw|

OpenStudy (anonymous):

oooh, okay. Your right, i just checked too. So it is logarithmic.

OpenStudy (amistre64):

i would say its some: 6 log(x) log(1)/log(6) = 0 log(6)/log(6) = 1 so this may be log_6(x) but its not for sure

OpenStudy (amistre64):

what is log(150)/log(6)?

geerky42 (geerky42):

Yeah it's \(log_6(x)\)since it contains \((2,36)\) as well

OpenStudy (amistre64):

lol, some b log(x) function

OpenStudy (amistre64):

2,36 is not that comprehansible. the only real point that may be verifiable is 6,1

OpenStudy (amistre64):

everything else is just a worse and worse guess. im only assuming that 1,0 is there

OpenStudy (anonymous):

2.80 okay thanks guys.

geerky42 (geerky42):

Well, one point isn't enough, right?

geerky42 (geerky42):

Could be transformed function.

OpenStudy (amistre64):

one point isnt enough .. thats why the graph is pretty useless and its anyones assumtion ...

OpenStudy (amistre64):

best guess is log(x)/log(6) also defined as log_6(x)

OpenStudy (anonymous):

Thanks!

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