Question

CALCULATIONS - gravimetric analysis (please check my answer ^_^
The data from an experiment to determine the % (by mass) of sulfate in lawn fertiliser are provided.

Mass of fertiliser sample =10.000 g
Mass of filter paper= 0.0250 g
Mass of filter paper and dry BaSO4 = 0.485 g

Calculate the percentage of sulfate in the fertiliser

Answer 1

Basically what i did was let y = mass of fertiliser sample
Therefore y= 10 g

Then we find the (formula mass of SO4) / (formula mass of BaSO4)
= 96.07 / 233.37 = 0.4117

Mass (SO4) = 0.4117 * mass (precipitate)
= 0.4117 * (0.485 - 0.0250)
= x g

% w/w = x/y * 100
= 1.89 %
Is that correct? I feel totally off xD

Answer 2

in "= 0.4117 * (0.485 - 0.0250) "

why did you write 0.485 and not 0.495?

Answer 3

oh snap. I made a typo in the question. It should be 0.485g NOT 0.495

Answer 4

it's good otherwise

Answer 5

thaaank you!