i need help with math questions
Everybody does :( But whats your question
simplify \[3\sqrt{5}-2\sqrt{7}+\sqrt{45}-\sqrt{28}\] please help?
Is there any answers?
yes sorry. A. \[2\sqrt{12}\] B. \[2\sqrt{2}\] C. \[6\sqrt{5}-4\sqrt{7}\] D. \[6\sqrt{10}-4\sqrt{14}\]
@iGreen Can you help with this??
Okay, we have to simplify the square root of 45 and the square root of 28. @rikkibracamonte1999
Okay :)
Okay, find the factors of 45 and 28..can you do that?
yes i can
Okay, tell me what you get.
Factors of 45: 1,3,5,9,15 and 45 Factors of 28: 1,2,4,7,14 and 28
Nice work, now which of those are perfect squares?
Do you know what a perfect square is?
no i do not
can you possibly explain it to me?
Okay, perfect squares are numbers that we can get by multiplying two whole numbers together. 81 is a perfect square because the square root of 81 is 9, which is a whole number. 121 is also a perfect square because the square root of 121 is 11, which is also a whole number.
Factors of 45: 1,3,5,9,15 and 45 Factors of 28: 1,2,4,7,14 and 28 So which of those numbers up there are perfect squares?
For 45 i am gonna say 1 and 45 For 28 i am gonna say 2 and 14
No, if you plug them into your calculator to find the square root, you get decimals..so they're incorrect.
sorry :)
i meant :(
math is not my best subject
Okay, 9 and 4 are the perfect squares. 9 because the square root of 9 is 3, and 4 because the square root of 4 is 2.
So we can break up the square root of 45 into: \(\sf \sqrt{9} \times \sqrt{5}\)
Okay :)
And the square root of 9 is what?
3
Yes, so we have: \(\sf 3 \times \sqrt{5}\) or \(\sf 3\sqrt{5}\)
We can break up the square root of 28 into: \(\sf\sqrt{4} \times \sqrt{7}\) What's the square root of 4?
2
Yes, so we have: \(\sf 2 \times \sqrt{7}\) or \(\sf 2\sqrt{7}\)
So we have: \(\sf 3\sqrt{5}-2\sqrt{7}+3\sqrt{5}-2\sqrt{7}\) Combine the like terms. \(\sf 3\sqrt 5 + 3 \sqrt 5 =~ \! ?\) \(\sf -2 \sqrt{7} - 2\sqrt 7\) Just add 3 + 3 and subtract -2 - 2 and keep the square roots.
so............ its b?
because i did what you said to do
You got it! \(\sf 3 \sqrt 5 + 3 \sqrt 5 = 6 \sqrt 5\) \(\sf -2 \sqrt 7 – 2 \sqrt 7 = -4 \sqrt 7\) So we have: \(\sf 6 \sqrt 5 – 4 \sqrt 7\)
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how about this? Is the simplified form of \[2\sqrt{3}\times2\sqrt{6}\] rational? A. Yes B. No
please help @iGreen . Your the best with these types of questions
@texaschic101 @iGreen @bohotness plz help?
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