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Mathematics 12 Online
OpenStudy (anonymous):

Solve as an Equality. |x-3| ≥ 3

OpenStudy (blazereh):

x + 3 ≥ 3

OpenStudy (blazereh):

I think :P

pooja195 (pooja195):

@blazereh thats right so far now solve that :)

pooja195 (pooja195):

@BlueNikeZ7 Lets not use that language

OpenStudy (anonymous):

Can you explain why |x-3| is = x + 3? I remember learning this, but I'm just mathed out :)

pooja195 (pooja195):

Ok so its asking you for the absolute value right? the absolute value of -3 is just 3

pooja195 (pooja195):

\[|x-3| ≥ 3\] Absolute value of -3 is just 3 and absolute value of postitive X is just X \[x+3 ≥ 3 \] now subtract 3 from both sides

geerky42 (geerky42):

\(|x-3| ≥ 3\) doesn't imply \(x+3 ≥ 3 \)

geerky42 (geerky42):

See: if it does, then we would have \(x\ge0\), right? Hmmm... Let \(x = 4\); we have \(|4-3|\ge3~~\Rightarrow~~|1|\ge3~~\Rightarrow~~1\ge3\) Is it true that \(1\ge3\)? @pooja195

geerky42 (geerky42):

Here, eat a snickers...

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