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Solve as an Equality. |x-3| ≥ 3
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x + 3 ≥ 3
I think :P
@blazereh thats right so far now solve that :)
@BlueNikeZ7 Lets not use that language
Can you explain why |x-3| is = x + 3? I remember learning this, but I'm just mathed out :)
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Ok so its asking you for the absolute value right? the absolute value of -3 is just 3
\[|x-3| ≥ 3\] Absolute value of -3 is just 3 and absolute value of postitive X is just X \[x+3 ≥ 3 \] now subtract 3 from both sides
\(|x-3| ≥ 3\) doesn't imply \(x+3 ≥ 3 \)
See: if it does, then we would have \(x\ge0\), right? Hmmm... Let \(x = 4\); we have \(|4-3|\ge3~~\Rightarrow~~|1|\ge3~~\Rightarrow~~1\ge3\) Is it true that \(1\ge3\)? @pooja195
Here, eat a snickers...
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