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Mathematics 8 Online
OpenStudy (anonymous):

What am I supposed to do when I get a question that asks me what value should be added to the expression to create a perfect square? Especially when there is no equal sign in the expression!

OpenStudy (anonymous):

ok... so its quadratic equations?

OpenStudy (anonymous):

Yeah...

OpenStudy (anonymous):

ok one sec

OpenStudy (anonymous):

This is the expression: \(x^2 + 16x\)

OpenStudy (anonymous):

ok so am i solving for x ?

OpenStudy (anonymous):

Yes. Can you give me a step-by-step explanation?

OpenStudy (anonymous):

ok... so it is equal to 0 right?

OpenStudy (anonymous):

I don't know. It doesn't say. ._.

OpenStudy (anonymous):

ok one sec lol :)

OpenStudy (anonymous):

ok i think u have to factor

OpenStudy (anonymous):

Hm. Okay!

OpenStudy (anonymous):

what an easy equation

OpenStudy (anonymous):

no im doing it @Niguyver

OpenStudy (anonymous):

?

OpenStudy (anonymous):

Haha. Not for me!

OpenStudy (anonymous):

nobody asked you that @conner143

OpenStudy (anonymous):

I don't like factoring... >_<

OpenStudy (anonymous):

lol... so... but one question @Niguyver

OpenStudy (anonymous):

ok so it is x^2+16x right

OpenStudy (anonymous):

so u cant factor out an x

OpenStudy (anonymous):

are you looking for the roots?

OpenStudy (anonymous):

i was going to factor it out like this \[(x+a)(x+a)\]

OpenStudy (anonymous):

Yes, but what number do we put as A?

OpenStudy (anonymous):

so i would say 4 and then the other would be 4x

OpenStudy (anonymous):

if you subtract you get a -16

OpenStudy (anonymous):

\[(x+4)(x+4x)\]

OpenStudy (anonymous):

and if you solve for x you would get a 0

OpenStudy (anonymous):

then set them both to 0 right @Niguyver

OpenStudy (anonymous):

مرحبا

OpenStudy (anonymous):

مرحبا بك أيضا.

OpenStudy (anonymous):

thanks blossom

OpenStudy (anonymous):

كيف حالك؟

OpenStudy (anonymous):

هل أنت عربي ؟ وزمان!

OpenStudy (anonymous):

right @Niguyver u set them both to 0?

OpenStudy (anonymous):

x=0 and if you subtract 16 you would get x= -16

OpenStudy (anonymous):

لا ايم ليس العربية . هل انت؟

OpenStudy (anonymous):

أنا جيد. :) ماذا عنك؟

OpenStudy (anonymous):

كلا . انا استخدم مترجم جوجل. لول

OpenStudy (anonymous):

ايم جيدة كذلك، ولكن هل أنت عربي ؟

OpenStudy (anonymous):

im using google as well :)

OpenStudy (anonymous):

لا، أنا لست العربية .

OpenStudy (anonymous):

Anyways, back to the math problem. :)

OpenStudy (anonymous):

haha yea...

OpenStudy (anonymous):

-16 is not one of the answers.

OpenStudy (anonymous):

Allow me to post the full question and its answers.

OpenStudy (anonymous):

so i would say set them both to 0 so x+4=0 and x+4x=0 then solve

OpenStudy (anonymous):

What value should be added to the expression to create a perfect square? \(x^2 + 16x\) A. 64 B. 4 C. 16 D. 8

OpenStudy (anonymous):

oh ........... lol one sec...

OpenStudy (anonymous):

64

OpenStudy (anonymous):

no maybe 8 lol

OpenStudy (anonymous):

and i have a question for u @BlossomCake

OpenStudy (anonymous):

@cobra-strikes

OpenStudy (anonymous):

What's the question?

OpenStudy (anonymous):

ok are you able to call dibs on a guy???

OpenStudy (anonymous):

What? How does that even relate to my MATH question??

OpenStudy (anonymous):

it doesnt lol someone is saying u can and im saying u cant so i had to ask u... lol

OpenStudy (anonymous):

I don't even understand what your question means anyways.

OpenStudy (anonymous):

ok if u like a guy and another girl likes him as well... are you able to call dibs on the guy???

OpenStudy (anonymous):

Um... I guess. @conner143

OpenStudy (anonymous):

Why?

OpenStudy (anonymous):

lol dang it...

OpenStudy (anonymous):

Why has it been danged? LOL

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