Write the integral in one variable to find the volume of the solid obtained by rotating the first-quadrant region bounded by y = 0.5x^2 and y = x about the line x = 7.
@Michele_Laino
@amistre64
what have we considered?
@amistre64
there are a few ways to approach this, the most obvious to me is called shells
what is a formula for determining the lateral area of a cylindar?
2πrh
good we can use this our height varies between the functions can you write me up a height function?
the formula for shells or washers is dx=pi(R^2-r^2)h
im working shells, 2pi rh is fine
a shell is a cylindar .
okay is the height function h=2pi(r) h=2pi(7) h=14pi
no, the height of an object is the distance from top to bottom if t(x) and b(x) bound the height, then t(x) - b(x) define the height at a given x what functions would we use for a top and bottom?
i dont know where tx and bx are
they are on your graph .... draw a cylindar around x=7 to see it better
you should know the region that is getting spun around ..... what function make up the top and bottom of that region?
the function that is being spin around is y=x
you are no where near the region that needs to be spun ....
|dw:1430431130914:dw|
|dw:1430427741359:dw|
y = 0.5x^2
|dw:1430431233007:dw|
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