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Mathematics 7 Online
OpenStudy (anonymous):

Write the integral in one variable to find the volume of the solid obtained by rotating the first-quadrant region bounded by y = 0.5x^2 and y = x about the line x = 7.

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (irishboy123):

@amistre64

OpenStudy (amistre64):

what have we considered?

OpenStudy (anonymous):

@amistre64

OpenStudy (amistre64):

there are a few ways to approach this, the most obvious to me is called shells

OpenStudy (amistre64):

what is a formula for determining the lateral area of a cylindar?

OpenStudy (anonymous):

2πrh

OpenStudy (amistre64):

good we can use this our height varies between the functions can you write me up a height function?

OpenStudy (anonymous):

the formula for shells or washers is dx=pi(R^2-r^2)h

OpenStudy (amistre64):

im working shells, 2pi rh is fine

OpenStudy (amistre64):

a shell is a cylindar .

OpenStudy (anonymous):

okay is the height function h=2pi(r) h=2pi(7) h=14pi

OpenStudy (amistre64):

no, the height of an object is the distance from top to bottom if t(x) and b(x) bound the height, then t(x) - b(x) define the height at a given x what functions would we use for a top and bottom?

OpenStudy (anonymous):

i dont know where tx and bx are

OpenStudy (amistre64):

they are on your graph .... draw a cylindar around x=7 to see it better

OpenStudy (amistre64):

you should know the region that is getting spun around ..... what function make up the top and bottom of that region?

OpenStudy (anonymous):

OpenStudy (anonymous):

the function that is being spin around is y=x

OpenStudy (amistre64):

you are no where near the region that needs to be spun ....

OpenStudy (amistre64):

|dw:1430431130914:dw|

OpenStudy (anonymous):

|dw:1430427741359:dw|

OpenStudy (anonymous):

y = 0.5x^2

OpenStudy (amistre64):

|dw:1430431233007:dw|

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