Question

An object on the end of a spring with spring
constant k moves in simple harmonic motion
with amplitude A and frequency f . Which of the
following is a possible expression for the kinetic
energy of the object as a function of time t ?

The answer is (1/2)k(A^2) cos^2((2pi)(f)(t)) but I don't understand how to solve for the answer. Can someone help me?

Answer 1

.

Answer 2

Do u know kinetic energy=.5kx^2

Answer 3

Nd displacement x=A*cos(2*pi*ft)

Answer 4

Kinetic energy=?

Answer 5

Yes, I do know both of those formulas.

Answer 6

Thank you so much! I just figured it out.

Answer 7

U r most welcome!!!!

Answer 8

But do u wanna know hw we get kinetic energy=.5kA^2

Answer 9

Sure!

Answer 10

Kinetic energy=work done

Answer 11

If u diplace ur spring by x, then the work done= .5kx^2

Answer 12

We need to do a integration for getting
Work done=.5kx^2

Answer 13

Oh ok, I get it.

Answer 14

Okk

Answer 15

Can you help me with another question?

Answer 16

Ya i wanna help u

Answer 17

Post another question plz!!!!!

Answer 18

Ok thanks, give me a minute