Question

PLEASE HELP, WILL GIVE MEDALS. PLEASE
Quick Computing Company produces calculators. They have found that the cost, c(x), of making x calculators is a quadratic function in terms of x.

The company also discovered that it costs $45 to produce 2 calculators, $143 to produce 4 calculators, and $869 to produce 10 calculators.

Find the total cost of producing 1 calculator.

Answer 1

Hi again, do you have multiple choice or is it typing?

Answer 2

No Multiple choice ... sadly

Answer 3

Can you tell me the options?

Answer 4

95

Answer 5

explanation:

Answer 6

c(x) = 9x^2 - 5x + 19

Answer 7

X=1 since we are solving for one claculator

Answer 8

But how can one be more than how much it costs to make two?

Answer 9

solve it out and 1 calculator = 95

Answer 10

Matlee did you come up with the same answer?? Sorry this just has to be 100% right. I can't miss anymore questions :'(

Answer 11

Ok let me check

Answer 12

I found where someone worked out the same problem just with different numbers if that helps anyone figure it out

Answer 13

Yes on yahoo answers right?

Answer 14

Yes this is the one of yahoo answers. KEEP IN MIND: different numbers, and for my problem you are solving for 1 calculator

Using the points (2, 45) (4, 143) and (10, 869), we can plug them into the following system of 3 equations using the y = ax^2 + bx + c format:

45 = a(2)^2 + b(2) + c
143 = a(4)^2 + b(4) + c
869 = a(10)^2 + b(10) + c

which simplifies to:

45 = 4a + 2b + c
143 = 16a + 4b + c
869 = 100a + 10b + c

Solving the system, we get a = 9, b = -5, and c = 19. Thus the equation is:

c(x) = 9x^2 - 5x + 19

If you have a TI graphing calculator, you can also enter the points by pressing Stat -> Edit and enter (2, 45) (4, 143) and (10, 869) into it. Go back and calculate the QuadReg of the points from the Calc tab and it will give you the same answer.

Now that we know the function that will produce the price of production for any number of calculators, plug in x = 7 and it will give you the price to produce 7 calculators.

c(x) = 9x^2 - 5x + 19
==> c(7) = 9(7)^2 - 5(7) + 19
==> c(7) = 441 - 35 + 19
==> c(7) = 425

Therefore, it costs $425 to produce 7 calculators.

Answer 15

So if you replace all the sevens with Ones you should get

Answer 16

c(x) = 9x^2 - 5x + 19
==> c(1) = 9(1)^2 - 5(1) + 19

Answer 17

So 9^2= 81 and 5(1)=5

Answer 18

c(1)=81-5+19

Answer 19

So you agree it's $95 ?

Answer 20

wait let me check this first

Answer 21

Okay take your time. The only thing I have to say is, why is one costing more than two

Answer 22

No idea but also making 4 calculator is like 40% more than to make 2 calculators times two

Answer 23

yes i agree 95

Answer 24

Okay I am about to enter it. Wish me luck! If it's wrong nonetheless you deserve a medal and all the thanks for taking the time to help me

Answer 25

It was wrong! but thank you for the help

Answer 26

Im so sorry i have no idea how that is wrong

Answer 27

Your welcome