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OpenStudy (kj4uts):

Which of the following are not trigonometric identities? Check all that apply. (attached below)

OpenStudy (kj4uts):

OpenStudy (kj4uts):

@amistre64

OpenStudy (kj4uts):

@jim_thompson5910

OpenStudy (amistre64):

all trig identites stem from the basic sin cos one .. what is the basic sin cos one?

OpenStudy (anonymous):

the correct identity is \[\sin^2(x) + \cos^2(x) = 1\]

OpenStudy (amistre64):

or we can have someone else determine it for you ... now we can divide by sin^2 or cos^2 and form the others ...

OpenStudy (amistre64):

fo simplicity i juat do s^2 + c^2 = 1 and work it from there

OpenStudy (kj4uts):

oh ok so sin and cos are trigonometric identities and the others are not

OpenStudy (amistre64):

no, this is the starting point, all the other trig identites will stem from this one.

OpenStudy (amistre64):

what happens when we divide by s^2?

OpenStudy (kj4uts):

when we divide by sin^2 im not exactly sure?

OpenStudy (amistre64):

divide it thru, show me the results you get

OpenStudy (kj4uts):

divide it thru?

OpenStudy (amistre64):

yeah, divide both sides by s^2 ... its a very basic mathematical process to do ... you hit the / key and then place next to it the s^2

OpenStudy (amistre64):

and it might help to knock off the obvious one s^2 + c^2 = 1 is not going to work out to be s^2 - c^2 = 1 is it?

OpenStudy (kj4uts):

no

OpenStudy (amistre64):

then lets pick D right off the bat lol, the rest we can either confirm or reject

OpenStudy (amistre64):

s^2 + c^2 = 1 ; divide both sides by s^2 (why?) s^2/s^2 + c^2/s^2 = 1/s^2 , simplify 1 + (c/s)^2 = (1/s)^2 what is another name for c/s and 1/s?

OpenStudy (amistre64):

do it again but divide by c^2 instead .... you get another trig identity

OpenStudy (kj4uts):

I looks like C. 1+cot^2 x = csc^2 x is a trigonometric identity

OpenStudy (anonymous):

http://www.sosmath.com/trig/Trig5/trig5/trig5.html

OpenStudy (amistre64):

it is yes

OpenStudy (kj4uts):

so far I think the others are not but I am still looking

OpenStudy (amistre64):

A and B are at odds with each other, dividing by c^2 should clear it up

OpenStudy (kj4uts):

ok so far I see that d is not c is and it looks like a and b are not to

OpenStudy (amistre64):

A and B are at odds with each other, one is right the other is wrong lets see how it works s^2/c^2 + c^2/c^2 = 1/c^2 (s/c)^2 + 1 = (1/c)^2 what can we conclude from this?

OpenStudy (amistre64):

since we have no (1/s)^2 one of them is clearly off tan^2 + 1 = sec^2 , does this look like it can match one of them?

OpenStudy (kj4uts):

@amistre64 we can match b

OpenStudy (amistre64):

yes, b is a match sec^2 - tan^2 = 1 is a fair rewrite of our identity

OpenStudy (kj4uts):

@amistre64 so b and d would be the answers to this problem. Thank you for your help and time :)

OpenStudy (amistre64):

um, we are looking for the ones that are NOT trig identies D fails from the start, but B is good .... and C is good that means A and D are what they are looking for

OpenStudy (kj4uts):

oh im sorrylol a and d because b and c are trigonometric identities thank you

OpenStudy (amistre64):

your welcome :)

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