Long Division Help! I forgot how to long divide and would like to learn. So how would you long divide 25378/184?
Please show work and explain steps
one what is to x=10 ----------------------------- x^2+8x +4 | 2x^4 + 5x^3 + 3x^2 + 7x + 8
@amistre64 I do not understand that
then you might have to just work it like we did back in the 3rd or 4th grade ....
Yeah that is actually what I wanted, a refresh mostly
hard to recall which grade it was really, been sooo long ago
But I would like to learn what you did there, I can divide polynomials using a box/grid method. Long division is really need though
well, we find an integer k such that 253 = 184k + r for some remainder r
if you can divide polys, divide the poly i presented
Okay, but I do now know how to do it with long division, the grid isn't accepted to my teacher
find an integer k such that 253 = 184k + r for some remainder r in other words we want 184k to be just smaller than 253
k=1 and r=69?
1 is good, 253 -184 ----- 69 thats good too, now drop down the next digit and do it again
1 -------- 184 | 25378 (184) ------- 697 697 = 184k + r for some other k and r this time
So 697=184k+r k=3 and r=145?
Does k have to be a whole number?
not really, but the algorithm is simpler if we let it be a whole number
Okay
So where are we at in terms of the |dw:1430445319738:dw|
for example 127 = 1(10^2) + 2(10^1) + 7(10)^0 but it could just as well be 127 = 2/3(10^2) + 1/5(10^1) + 175/3(10)^0
13 -------- 184 | 25378 (184)vv ----- 697v (552)v ---- 1458
This time k=7 r=170
So just repeat and add decimal later?
then we have come to the end of it 170 out of 184 is left over
if youwant to decimate it sure ....
Okay great, now what were you doing with the polys and how did you make them?
25378 = 184(137) + 170
well since our number system is base 10 each position has a digit that is multiplied by a power of 10 instead of 10, let it be x and you have a polynomial representaiton of the numbers
Oh okay that is easy, then divide the polys, and what does the answer of the polys mean? Same base 10 concept?
yeah, itll be the same number but in a base x representation, let x = 10 again 2x^2 -11x +83 ----------------------------- x^2+8x +4 | 2x^4 + 5x^3 + 3x^2 + 7x + 8 (2x^4+16x^3 +8x^2) -------------------- -11x^3 -5x^2 +7x +8 (-11x^3-88x^2 -44x) -------------------- 83x^2 + 51x +8 (83x^2+664x +332) ------------------ -613x -324 200 - 110 + 83 = 173 not too sure if i got the last part (the remainder) worked out right tho
Oh okay, thank you so very much for the great amount of help! Okay and final question, I know I won't be any time soon, but how does one become a moderator?
one does not become a moderator, one is chosen for the position.
Oh okay, I thanks for clearing that up. Okay so thank you very much for the help!
youre welcome
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