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Chemistry 21 Online
OpenStudy (joannablackwelder):

How much energy is contained in 1 mol of each of γ -ray photons with a wavelength of 2.72×10−5 nm.

OpenStudy (joannablackwelder):

@abb0t

OpenStudy (joannablackwelder):

I got 4.40 x 10^12 J. Can anyone confirm?

OpenStudy (joannablackwelder):

@aaronq

OpenStudy (abb0t):

Use the equation: \(\sf \color{red}{E = hv = h\frac{c}{\lambda}}\) this is when you're referring to a photon, which you are here: c = speed of light = 3.0 x 10\(^8 \frac{m}{s}\) h = planks constant = 6.626 x 10\(^{-34}\) J • s \(\lambda\) = wavelength (make sure it is in meters to match with units for speed of light). Hence, convert nm \(\rightarrow\) m 1 m = 10\(^{9}\)nm

OpenStudy (joannablackwelder):

Yeah, I did that. Did you get a different answer?

OpenStudy (joannablackwelder):

@abb0t

OpenStudy (aaronq):

After you use the equation abb0t provided (planck's equation gives the energy of one photon) you need to multiply by avogadro's number.

OpenStudy (joannablackwelder):

Thanks, @aaronq, I did that too. :-) Do you get 4.40 x 10^12 J too?

OpenStudy (aaronq):

yes, it works out to that number

OpenStudy (joannablackwelder):

Thanks so much!

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