Question

Stuck

Answer 1

Which set of side lengths shows similar triangles?

Triangle ABC : 110, 80, 60; Triangle XYZ: 6, 8, 5.5
Triangle ABC : 32, 20, 32; Triangle XYZ: 30, 16, 16
Triangle ABC : 30, 20, 60; Triangle XYZ: 40, 60, 90
Triangle ABC : 40, 20, 50; Triangle XYZ: 10, 4, 8

Answer 2

what is your guess?

Answer 3

@TobleroneJesus I don't have one

Answer 4

@dan815

Answer 5

Note: For this explanation I'm going to replace Triangle ABC with "Triangle 1" and Triangle XYZ with "Triangle 2".

Hint: Similar triangles have a scalar (some number that multiplies the values) of one side of Triangle 1 to get the same length of the same side of Triangle 2. That scalar should be able to multiply all sides of Triangle 1 to get all the lengths of Triangle 2. It doesn't matter what the scalar is in this problem, but what matters is whether Triangle 1 or Triangle 2 is a scalar of the other triangle. Think of ratios.

Answer 6

I would say Triangle ABC : 40, 20, 50; Triangle XYZ: 10, 4, 8
triangle ABC is 5 times the amount of each side of XYZ --> 10*5=50 which is one side of ABC, 4*5=20 is another side of triangle ABC, 8*5=40 which is the last side of the triangle

Answer 7

Yes, @hockeychick23 is right. Remember that triangles can still be the same if they are rotated or flipped so the side A doesn't have to be similar to side X, side B to side Y, or side C to side Z. In this instance side C was a scalar of side X, side B of side Y, and side A of side Z.

Answer 8

thank you @hockeychick23 and @hadenthefox :D