Question

Stats help please?

Answer 1

http://gamutech.com
We'll help with questions you have there and there's a chat no lag like OS and you won't get suspended

Answer 2

@perl

Answer 3

we have to find the mean value first

Answer 4

oh ok, do i find the mean for x or p? @Michele_Laino

Answer 5

by definition, the mean value is given by the subsequent computation:
\[\Large \left\langle x \right\rangle = \left( {4 \times \frac{1}{3}} \right) + \left( {3 \times \frac{1}{{12}}} \right) + \left( {2 \times \frac{7}{{12}}} \right) = ...?\]

Answer 6

ok thanks, so i got 4/3+ 3/12+ 14/12= 16/12+3/12+14/12= 33/12= 2.75

Answer 7

that's right!

Answer 8

now, we have to compute this:
\[\large \begin{gathered}
{\sigma ^2} = \left\{ {{{\left( {4 - \frac{{33}}{{12}}} \right)}^2} \times \frac{1}{3}} \right\} + \left\{ {{{\left( {3 - \frac{{33}}{{12}}} \right)}^2} \times \frac{1}{{12}}} \right\} + \hfill \\
+ \left\{ {{{\left( {2 - \frac{{33}}{{12}}} \right)}^2} \times \frac{7}{{12}}} \right\} = ...? \hfill \\
\end{gathered} \]

Answer 9

oh ok so i have (15/12)^2= (5/4)^2*(1/3)= 1.5626*1/3= .52086667 + (1/4)^2= 0.0625+.52086667+ (-9/12)^2= 0.0625+.52086667+.328125= .91149167

Answer 10

I got 0.8532

Answer 11

so we have:
\[\sigma = \sqrt {0.853} = 0.924\]

Answer 12

ok thanks! sorry it took so long to respond my internet crashed @michele_laino

Answer 13

sorry I have lost my internet connection