Question

Evaluate the velocity of a body and its distance moved, both after 2 minutes from it starts from rest, when its acceleration is given by a = 15 m/s^2

Answer 1

Appreciate any help... Really stuck .. Thanks :)

Answer 2

this is constant acceleration, so you can use these equations of motion
\[v = u + at \\ x = ut + \frac{1}{2} a t^2\]

u, initial velocity = 0, starts "at rest"; v = velocity you are looking for
x = distance travelled, you are also looking for
t = time: careful with these units

but, if you're actually supposed to be learning calculus, derive the equations from the givens.

Answer 3

acceleration = velocity / time

so after 2 minutes (120 seconds)
15 = v / 120

so solve for v can you do that ?

Answer 4

So for V will it be a(15) x t (120)
= 1800 m/s ?

Answer 5

yes

Answer 6

So distance travelled is 108000m^2?

Answer 7

s = 1/2 a t^2
= 7.5 * 1800^2

Answer 8

since ut = 0 ( the object starts from rest)

Answer 9

these equations are for constant acceleration and are derived using calculus .
I assume you haven't done any calculus yet?

Answer 10

This is for a calculus paper

Answer 11

i see - then you should use calculus
unfortunately i have to go now so someone else may help you

Answer 12

I know but ai don't know how - that's why I need help with it :/

Answer 13

Evaluate the velocity of a body and its distance moved, both after 2 minutes from it starts from rest, when its acceleration is given by a = 15 m/s^2