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integrate 1/x^1.005
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\[\int\limits x^n dx = \frac{x^{n+1}}{n+1}\] here n = ???
no wait, it's a fraction. it's 1 / x^1.005 not just the x
\[\int \frac{1 }{ x^{1.005}} dx = \int x^{-1.005} dx\]
yes?
that's what i did also. then whats next?
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you add 1 right? and the answer is the denominator?
this what you mean? \[\frac{x^{(-1.005 + 1)}}{-1.005 + 1}\]
yes
is that correct
simplify it ... -1.005 + 1 = -0.05 and 1/ 0.005 = 200 .....but yes, well done.
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wait can you explain to me the simplification
\[\frac{x^{-1.005 + 1}}{-1.005 + 1} = \frac{x^{-0.005}}{-0.005} = \frac{-200}{x^{0.005}}\]
thanks!
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