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Find the axis of symmetry for this parabola: y = -x2 − 2x − 5 is -3 the axis of symmetry
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Hold on I'll help. Just need a second
x^2 + 2x - 5 = y Now we need to rearrange x^2 + 2x + ? = y-5
the axis of a parabola y = ax^2+bx+c, is given by the subsequent equation:: \[\Large x = - \frac{b}{{2a}}\]
in this case a = 1, and b = 2 right? @Michele_Laino
I think a=-1 and b=-2 since we have to look at the original equation
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oh yes I forgot that there are negative values
So that means the equation would be\[x= -\frac{ -2 }{ 2(-1)}\]
Or \[x = -\frac{ -2 }{ -2 }\]
Or \[x = - \frac{ 1 }{ 1 }\]
Or x = 1
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@Michele_Laino
I thin, it is x=-1
think*
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