Question

An automobile traveling 10 mi/hr has wheels 36 inches in diameter. If the car is brought to a stop uniformly in 74 turns of the wheels, what is the magnitude of the angular acceleration of the wheels (in radians/second^2)?

So i've found just the radians/sec which is 9.77. After that i'm not quite sure where to go. I'm I supposed to use those "kinematic" equations?

Answer 1

Can u tell me retardation a=?

Answer 2

Use
v^2=u^2-2as
a=?

Answer 3

Given
v=0
u=10mi/h=?inch/sec
s=74turn*circumference of wheel=74*pi*diameter of wheel=74*pi*36=?inches

Answer 4

U know
a=alpha*r
Alpha=?

Answer 5

Alpha=angular acceleration

Answer 6

r=radius of wheel=36/2=?inches