Can someone please help me solve this question:
Simplify and select the answer with the appropriate restrictions for the variables.
$$(x~+~5)(x~+~3)\over5x~+~15$$

Question

anonymous · Answer

I know that x $\neq $ -3.

anonymous · Answer

x2+83x+15 over 5x  see if this works

anonymous · Answer

What am I supposed to do with that? How did you get an 83?

sleepyhead314 · Answer

factor the bottom and get
5(x+3)
right?
then the (x+3) can cancel each other in the numerator and denominator
because they cancel, there will be a Hole at x = -3

anonymous · Answer

How can 5x + 15 factor to 5(x + 3)?

sleepyhead314 · Answer

5*x + 5*3
bring the 5's to the front
(backwards Distributive Property)
5 (x + 3)

anonymous · Answer

Oh! Okay, now I understand!

anonymous · Answer

So the answer is $\Huge~x~+~5\over\Huge~5$ where x $\neq $ -3.

anonymous · Answer

Thanks for the help! @sleepyhead314 :D

anonymous · Answer

sorry i looked at it wrong

anonymous · Answer

It is okay. :)