Question

Medals!!!! :D
Determine two pairs of polar coordinates for the point (2, -2) with 0° ≤ θ < 360°.

Answer 1

Answer choices:
a. (2 square root of 2, 225°), (-2 square root of 2, 45°)
b. (2 square root of 2, 135°), (-2 square root of 2, 315°)
c.(2 square root of 2, 315°), (-2 square root of 2, 135°)
d.(2 square root of 2, 45°), (-2 square root of 2, 225°)

Answer 2

@TheStarlingHasFlown @amistre64 ^.^

Answer 3

@Michele_Laino @Keygrover @BloomLocke367 somebody help me please....

Answer 4

we have to apply these formulas, in order to change from cartesian coordinates (x,y) to polar coordinates (r, \theta):
\[\left\{ \begin{gathered}
x = r\cos \theta \hfill \\
y = r\sin \theta \hfill \\
\end{gathered} \right.\]

Answer 5

from those formulas, we get:
\[r = \sqrt {{x^2} + {y^2}} \]

Answer 6

okay....

Answer 7

in our case, we have:
\[r = \sqrt {{x^2} + {y^2}} = \sqrt {{{\left( { - 2} \right)}^2} + {2^2}} = ...?\]

Answer 8

what is r?

Answer 9

\[r = \sqrt {{x^2} + {y^2}} = \sqrt {{2^2} + {{\left( { - 2} \right)}^2}} = \sqrt {4 + 4} = ...?\]

Answer 10

2sqrt2??

Answer 11

that's right!

Answer 12

oh :)

Answer 13

now, starting from my transformation formulas, we get:
\[\Large \tan \theta = \frac{y}{x}\]

Answer 14

so, in our case , we have:
\[\Large \tan \theta = \frac{y}{x} = \frac{{ - 2}}{2} = ...?\]

Answer 15

what is the value of
\[\tan \theta \]

Answer 16

\[\tan \theta-1??\]

Answer 17

right!
\[\tan \theta = \frac{y}{x} = \frac{{ - 2}}{2} = - 1\]

Answer 18

oh! :) i'm not used to being right in math!! X)

Answer 19

i wasn't sure if i understood exactly what you were asking

Answer 20

so, what is theta?
please keep in mind that drawing: