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Mathematics 15 Online
OpenStudy (anonymous):

An observer (O) is located 660 feet from a tree (T). The observer notices a hawk (H) flying at a 35° angle of elevation from his line of sight. How high is the hawk flying over the tree? You must show all work and calculations to receive full credit.

OpenStudy (anonymous):

OpenStudy (campbell_st):

use the tan ratio to find the height

OpenStudy (anonymous):

I know its opposite/adjacent but thats about all i know lol

OpenStudy (anonymous):

Well angle H is 35º because of alternate interior angles

OpenStudy (anonymous):

Angle OHT is 55º because it is a complementary angle with angle H and must add up to 90º

OpenStudy (anonymous):

Now that we know that we know two angle measurements of triangle OHT we can figure the problem out by using the ASA postulate

OpenStudy (anonymous):

Im confused, ive never heard of ASA postulate. lol I know have to use the tangent ratio somewhere in this problem lol .

OpenStudy (anonymous):

sorry im brain dead when it comes to math

OpenStudy (anonymous):

You actually need to use sin

OpenStudy (anonymous):

The answer is 462.136975218 or 462.14

OpenStudy (anonymous):

how did you get that ?

OpenStudy (anonymous):

I used sin

OpenStudy (anonymous):

\[(660•\sin(35))/\sin(55)\]

OpenStudy (anonymous):

how do i prove where i got the 55 from

OpenStudy (anonymous):

nevermind i get it, lol thankyou

OpenStudy (campbell_st):

the answer to the question is as simple \[\tan(35) = \frac{h}{660}\] make h the subject and you get \[h = 660 \times \tan(35)\] calculate the value of h, and then you can answer how high the hawk is. hope it makes sense

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