An observer (O) is located 660 feet from a tree (T). The observer notices a hawk (H) flying at a 35° angle of elevation from his line of sight. How high is the hawk flying over the tree? You must show all work and calculations to receive full credit.
use the tan ratio to find the height
I know its opposite/adjacent but thats about all i know lol
Well angle H is 35º because of alternate interior angles
Angle OHT is 55º because it is a complementary angle with angle H and must add up to 90º
Now that we know that we know two angle measurements of triangle OHT we can figure the problem out by using the ASA postulate
Im confused, ive never heard of ASA postulate. lol I know have to use the tangent ratio somewhere in this problem lol .
sorry im brain dead when it comes to math
You actually need to use sin
The answer is 462.136975218 or 462.14
how did you get that ?
I used sin
\[(660•\sin(35))/\sin(55)\]
how do i prove where i got the 55 from
nevermind i get it, lol thankyou
the answer to the question is as simple \[\tan(35) = \frac{h}{660}\] make h the subject and you get \[h = 660 \times \tan(35)\] calculate the value of h, and then you can answer how high the hawk is. hope it makes sense
Join our real-time social learning platform and learn together with your friends!