Equivalent Expressions. Help?
You already asked this question: http://openstudy.com/users/shaleiah#/updates/55415b47e4b05c587d02ad4b Just use exponent rule: \[\large \dfrac{a^m}{a^n} = a^{m-n}\] For example: \(\large \dfrac{s^{12}}{s^7} = s^{12-7} = s^5\)
Can you use exponent rule here? @shaleiah
No.
Why not? What part are you struggling with?
Never heard of the exponent rule. Do I add all the exponents and then use the rule?
Really, what did you learn other than exponent rule? To apply exponent rule, you just subtract exponent from numerator by exponent from denominator. Again for example: \(\dfrac{b^5}{b^3} = b^{5-3} = b^2\) See what I did with exponents, right?
\[\frac{ 64p^4 }{ 112p^8}=b^8-4=b^4\]
Actually \(\dfrac{p^4}{p^8}=p^{4-8}\)
\[\cdots=p^{-4} = \dfrac{1}{p^4}\]
Because exponent in numerator is smaller than exponent in denominator. does that make sense?
yes
Ok, so you simplified exponent for variable p;\[ \dfrac{64}{112}\cdot\dfrac{p^4}{p^8}\cdot\dfrac{q^6}{q^2}\cdot\dfrac{r^4}{r^{12}} ~~=~~ \dfrac{64}{112}\cdot\dfrac{1}{p^4}\cdot\dfrac{q^6}{q^2}\cdot\dfrac{r^4}{r^{12}}\] Now use that rule on variable q.
What is \(\dfrac{q^6}{q^2}\)?
\[\frac{ q^6 }{ q^2 }=q ^{6-2}\]
\[q=4\]
\(q^4\)
Yeah
Do you understand how to use exponent rule now?
yes, thank you.
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