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Mathematics 14 Online
OpenStudy (shaleiah):

Equivalent Expressions. Help?

geerky42 (geerky42):

You already asked this question: http://openstudy.com/users/shaleiah#/updates/55415b47e4b05c587d02ad4b Just use exponent rule: \[\large \dfrac{a^m}{a^n} = a^{m-n}\] For example: \(\large \dfrac{s^{12}}{s^7} = s^{12-7} = s^5\)

geerky42 (geerky42):

Can you use exponent rule here? @shaleiah

OpenStudy (shaleiah):

No.

geerky42 (geerky42):

Why not? What part are you struggling with?

OpenStudy (shaleiah):

Never heard of the exponent rule. Do I add all the exponents and then use the rule?

geerky42 (geerky42):

Really, what did you learn other than exponent rule? To apply exponent rule, you just subtract exponent from numerator by exponent from denominator. Again for example: \(\dfrac{b^5}{b^3} = b^{5-3} = b^2\) See what I did with exponents, right?

OpenStudy (shaleiah):

\[\frac{ 64p^4 }{ 112p^8}=b^8-4=b^4\]

geerky42 (geerky42):

Actually \(\dfrac{p^4}{p^8}=p^{4-8}\)

geerky42 (geerky42):

\[\cdots=p^{-4} = \dfrac{1}{p^4}\]

geerky42 (geerky42):

Because exponent in numerator is smaller than exponent in denominator. does that make sense?

OpenStudy (shaleiah):

yes

geerky42 (geerky42):

Ok, so you simplified exponent for variable p;\[ \dfrac{64}{112}\cdot\dfrac{p^4}{p^8}\cdot\dfrac{q^6}{q^2}\cdot\dfrac{r^4}{r^{12}} ~~=~~ \dfrac{64}{112}\cdot\dfrac{1}{p^4}\cdot\dfrac{q^6}{q^2}\cdot\dfrac{r^4}{r^{12}}\] Now use that rule on variable q.

geerky42 (geerky42):

What is \(\dfrac{q^6}{q^2}\)?

OpenStudy (shaleiah):

\[\frac{ q^6 }{ q^2 }=q ^{6-2}\]

OpenStudy (shaleiah):

\[q=4\]

geerky42 (geerky42):

\(q^4\)

geerky42 (geerky42):

Yeah

geerky42 (geerky42):

Do you understand how to use exponent rule now?

OpenStudy (shaleiah):

yes, thank you.

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