Question

PLEASE help!

FAN + MEDAL:


Which value is equivalent to
(8x4x2/8x7)^2 x (8^0/7^-3)^3 x 7^-9?

64/49
8/49
16/7
512/7

Answer 1

Have you tried simplifying each expression inside the parenthesis?

Answer 2

no, can I do it real quick?

Answer 3

so.... if you were to say, as hadenthefox said, simplify say \(\bf \cfrac{8x^4x^2}{8x^7} \)

what would that give you?

Answer 4

96/59

Answer 5

96/59? the "x" went MIA there

Answer 6

@jdoe0001 his problem isn't using x as a variable but instead as an operator I bleieve

Answer 7

hmmm

Answer 8

the x means multiplication & she

Answer 9

I thought the "x" just meant "x"... hmmm so is multiplication?

Answer 10

yes

Answer 11

so \(\bf \left( \cfrac{8\cdot 4\cdot 2}{8\cdot 7} \right)^2 \cdot \left( \cfrac{8\cdot 0}{7\cdot {-3}} \right)^3\cdot 7\cdot {-9} ?\)

Answer 12

yes

Answer 13

wait for the 8 x 0 it's suppouse to be 8^0 . 0 is an exponent

Answer 14

ok so.. hmm so what's say 8 * 0 = ?

Answer 15

no, the 7 is to the power of -9, not multiplied by -9

Answer 16

hmmm lemme redo that then.. there are a few exponents I notice

Answer 17

the 0, -3, & -9 are exponents

Answer 18

ok hold the mayo

Answer 19

what

Answer 20

keep in mind this -> \(\bf a^{-{\color{red} n}} \implies \cfrac{1}{a^{\color{red} n}}\qquad \qquad

\cfrac{1}{a^{\color{red} n}}\implies a^{-{\color{red} n}}
\\ \quad \\
% negative exponential denominator
a^{{\color{red} n}} \implies \cfrac{1}{a^{-\color{red} n}}
\qquad \qquad

\cfrac{1}{a^{-\color{red} n}}\implies \cfrac{1}{\frac{1}{a^{\color{red} n}}}\implies a^{{\color{red} n}} \)

Answer 21

So @TheHangingTree here are some important exponent rules to recall for this problem and