Jered's parents are going to repaint their house. They need to select two colors to complete the job. If they previously narrowed their decision down to six colors, how many combinations of two can they choose from?
A. 12
B. 15
C. 30
D. 3
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OpenStudy (chycora):
a or d
OpenStudy (studygurl14):
Neither.
OpenStudy (chycora):
i'm really thinking a
OpenStudy (chycora):
then it's c
OpenStudy (studygurl14):
No, not that either.
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OpenStudy (chycora):
ok then i'm confused
OpenStudy (studygurl14):
nCr, that's what you're doing. n = total to choose from, r= number of items you take from the n
\(\Large\frac{n!}{(n-r)!r!}\)
OpenStudy (chycora):
how
OpenStudy (studygurl14):
n = 6, r=2, plug in and solve
OpenStudy (kendricklamar2014):
@Agl202 if its not A, C, or D. Well of course its B
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OpenStudy (chycora):
i gt 3 so like i said d
OpenStudy (studygurl14):
How did you get 3? @chycora
Remember that 6! = 6 x 5 x 4 x 3 x 2 x 1
OpenStudy (chycora):
so when i do that i get 720 that is nt even close to 15 so still don't get it
OpenStudy (studygurl14):
That's not the whole formula. Look u p there^ to see all of it.
OpenStudy (studygurl14):
\(\Large\frac{6!}{(6-2)!2!}\)
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