Question

The probabilities of the orphaned pets in six cities' animal shelters being different types of animals are given in the table. If a randomly selected orphaned pet in a St. Louis animal shelter is a dog, what is the probability that it is a mastiff?

15.30%

18.15%

21.04%

21.84%

Answer 1

thanks for helping

Answer 2

wheres the table?

Answer 3

hold on oe sec

Answer 4

City Cat Dog−
Lhasa Apso Dog−
Mastiff Dog−
Chihuahua Dog−
Collie
Austin 24.5% 2.76% 2.86% 3.44% 2.65%
Baltimore 19.9% 3.37% 3.22% 3.31% 2.85%
Charlotte 33.7% 3.25% 3.17% 2.89% 3.33%
St. Louis 43.8% 2.65% 2.46% 3.67% 2.91%
Salt Lake City 28.9% 2.85% 2.78% 2.96% 2.46%
Orlando 37.6% 3.33% 3.41% 3.45% 2.78%
Total 22.9% 2.91% 2.68% 3.09% 2.58%

Answer 5

sorry it did not come out right

Answer 6

post a PICture

Answer 7

do you see the link

Answer 8

focus on the "st louis" row only

highlight the dog columns

Answer 9

Add up those percentages and then divide the mastiff percentage by the total you previously got

P(mastiff) = (mastiff percentage)/(sum of highlighted percentages)

Answer 10

so how do i get the answer

Answer 11

what did i do wrong i got 11.69

Answer 12

helo?

Answer 13

P(mastiff) = (mastiff percentage)/(sum of highlighted percentages)

P(mastiff) = (2.46)/(11.69)

P(mastiff) = ??

Answer 14

divide

Answer 15

yes

Answer 16

ok im dumb now i got 0.210

Answer 17

wait never mind it 21.04

Answer 18

it should be 21.04%, yes

Answer 19

thats not one of the answer choices please help ?