Question

displacement and distance traveled problem using a graph. I don't think you really need to read the entire question. Just the last part where the question is and then use the graph or table to approximate. I can't seem get the right answer though. For the first problem I tried adding the area but I guess that's not how you do it.

Answer 1

@xapproachesinfinity do you know how to do this by any chance :)

Answer 2

@freckles

Answer 3

\[s'(t)=v(t) \\ \text{ or you can write this relationship as } \\ s(t)=\int\limits v(t) dt\]

hmmm and seems it wants you to use riemann sum instead of integrals

oh and cool stuff they have the rectangles they want you to use in the pic

and they also tell you exactly how to find the total displacement

Answer 4

let me check your displacement real quick

Answer 5

but i don't have the equation so I go off by the graph..

Answer 6

not sure if i add wrong.

Answer 7

you are actually really close

Answer 8

unless I added wrong

Answer 9

what did u get?

Answer 10

you have the base of each rectangle is 1
the sum of the areas of the rectangle is
1(the height of each rectangle)
1(-2-3+4+3+4+2+1+2)

Answer 11

I think I know what you did you added 9 rectangle heights together
you are only suppose to use the 8 in the drawing

Answer 12

ok kk. And then what would ido with distance ?

Answer 13

I think you can find total distance traveled by doing
the absolute value of those first two "negative heights" plus the other positive heights

Answer 14

like you know same thing I have above except change the -2 to 2
and the -3 to 3

Answer 15

ok i understand. Thanks @freckles

Answer 16

@freckles & @schoolKid11 : @freckles is correct; distance simply takes into account magnitude (but not direction) hence it is a scalar quantity; displacement is a vector which takes into account both magnitude & direction.