In ΔABC shown below, segment DE is parallel to segment AC:
The two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally:
Statement Reason 1. Line segment DE is parallel to line segment AC 1. Given 2. Line segment AB is a transversal that intersects two parallel lines. 2. Conclusion from Statement 1. 3. 3. 4. ∠B ≅ ∠B 4. Reflexive Property of Equality 5. 5. 6. BD over BA equals BE over BC 6. Converse of the Side-Side-Side Similarity Theorem Which statement and reason accurately completes the proof?
3. ∠BDE ≅ ∠BAC; Corresponding Angles Postulate 5. ΔBDE ~ ΔBAC; Angle-Angle (AA) Similarity Postulate 3. ΔBDE ~ ΔBAC; Corresponding Angles Postulate 5. ∠BDE ~ ∠BAC; Angle-Angle (AA) Similarity Postulate 3. ∠BDE ≅ ∠BAC; Congruent Angles Postulate 5. ΔBDE ~ ΔBAC; Angle-Angle (AA) Similarity Postulate 3. ∠BDE ≅ ∠BAC; Congruent Angles Postulate 5. ΔBDE ~ ΔBAC; Side-Angle-Side (SAS) Similarity Postulate
It was A btw, for all you future Geometry Students c;
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