Question

x^2+4y^2-16=0 what are the x and y intercepts

Answer 1

Hley Gina :)

The y-intercept is the location where we intercept the y axis.
This happens when x=0.\[\Large\rm x^2+4y^2-16=0\]\[\Large\rm 0+4y^2-16=0\]What do you get for your y values?

Answer 2

x^2+0-16=0?

Answer 3

That's a good approach for finding your `x-intercepts`,
by setting the y equal to 0.

But let's them separately! :)
Let's find our y-intercepts first.
Need to solve for y here,\[\Large\rm 0+4y^2-16=0\]

Answer 4

We would like to isolate our y.
We'll start by doing the most simple steps first.

We have a 16 being subtracted, so we'll do the opposite, we'll add 16 to each side, ya?

Answer 5

\[\Large\rm 4y^2\cancel{-16+16}=0+16\]\[\Large\rm 4y^2=16\]

Answer 6

What about the next step?
We have a 4 multiplying our y^2.
How do we undo multiplication? What's the opposite operation we can perform? :o

Answer 7

4 divided by 16

Answer 8

16 divided by 4*
yes :)

Answer 9

16/4 wich is y^2=4 then sqaure root both sides so y=2

Answer 10

Well something fancy happens when we take the `square root` of a `square`.
We end up with a plus or minus. We get two solutions! :)

So we're actually going to get y=2, y=-2.
k? :3

Answer 11

right

Answer 12

And then it looks like you already had the right approach for starting to find your x-intercepts:\[\Large\rm x^2+0-16=0\]

Answer 13

Do some similar steps to what we did before, try to find some x values :D

Answer 14

+16 to other side so it reads x^2=16

Answer 15

square root each side to get +4 and -4

Answer 16

Yayyy good job \c:/

Oh also,
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