A triangle has vertices P(1, 3), Q(3, 5), and R(6, 2). The slope of the median to QR is?
@acxbox22
plot the three coordinates
don't you just find the slope of QR since slope doesn't change in a line
lemme fix that
you find the midpoint of QR then you find the slope of the point opposite side QR and the midpoint of QR
ok i graphed it
\(\bf \textit{middle point of 2 points }\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) Q&({\color{red}{ 3}}\quad ,&{\color{blue}{ 5}})\quad % (c,d) R&({\color{red}{ 6}}\quad ,&{\color{blue}{ 2}}) \end{array}\qquad % coordinates of midpoint \left(\cfrac{{\color{red}{ x_2}} + {\color{red}{ x_1}}}{2}\quad ,\quad \cfrac{{\color{blue}{ y_2}} + {\color{blue}{ y_1}}}{2} \right)\) anyhow, find the median point and use that with the point P to get the slope for that
why would i use p
|dw:1430609672663:dw|
yep except r should be lower than p
hmmm "not drawn to scale" :P
wait i understand what the question is asking now
but you're correct, it is lower than P
the slope of midpoint of QR and P
midpoint is (-3/2,3/2)
1.5/2.5
but thats not an answer
@jdoe0001
hmmm
I guessed and somehow the answer is 1/7?
well.. your midpoint is .... off for one I got something else
what did you get?
wait nevermind I screwed up my numbers oops
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) Q&({\color{red}{ 3}}\quad ,&{\color{blue}{ 5}})\quad % (c,d) R&({\color{red}{ 6}}\quad ,&{\color{blue}{ 2}}) \end{array}\qquad % coordinates of midpoint \left(\cfrac{{\color{red}{ 6}} + {\color{red}{ 3}}}{2}\quad ,\quad \cfrac{{\color{blue}{ 2}} + {\color{blue}{ 5}}}{2} \right)\implies ?\)
Thank you I did it again and got 1/7
yeah thats what i did the second time
(1.5,2.5)
well... yes but it happens to give a slope of 1/7, yes but with the correct midpoint
Yep I messed up, but i got to it, thank you for helping me
yw
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