Question

Need help with this Radical Equation! I'll put it in the comments.

Answer 1

\[2\sqrt{2x - 1} + 7 = 10\]

Answer 2

@Nnesha Need your help :)

Answer 3

okay in order to get rid of radical first move 7 and 2 to the right side o^_^o

Answer 4

alright let me try

Answer 5

good! :-)

Answer 6

\[\sqrt{2x-1} = 1\]

Answer 7

and how did you get that ??

Answer 8

i subtracted both 2 and 7 to the right side, I think I may have dun goofed

Answer 9

nope 2 is multiplying with the radical
so you should do opposite of multiply in order to cancel out 2 from left side

Answer 10

Silly me so I divided it and subtracted it with 7 and now I got \[\sqrt{2x+1}=-2\]

Answer 11

first subtract then divide

Answer 12

alright so is it okay if its a fraction?

Answer 13

yes that's fine it's g oing to be fraction form

Answer 14

alright so now its \[\sqrt{2x-1}=\frac{ 3 }{ 2 }\]

Answer 15

yep right what would be ur next step!

Answer 16

square both sides to get rid of square root

Answer 17

yep!

Answer 18

Umm, I'm not to good sure how to square a fraction, could you help me out?

Answer 19

sure \[\huge\rm (\frac{ x }{ y })^2 = \frac{ x^2 }{ y^2 }\]
square of numerator and denominator

Answer 20

thanks, so it will be \[2x+1=\frac{ 9 }{ 4 }\]

Answer 21

yep right

Answer 22

alrighty than I do the usual equation where I subtract 1 and 9/4 then divide 2x

Answer 23

divide by what ?? :o

Answer 24

2x

Answer 25

you should isolate x

Answer 26

okay first subtract 1 let me know what you get
then i'll tell u what to do next :-)

Answer 27

can you do that part for me please :/

Answer 28

ok

Answer 29

can you solve right side ?