Question

Integrate 9^x using the Right Riemann Sum with 4 intervals from x=0 to x=2

Answer 1

I got to
\[\frac{ 1 }{ 2 }\sum_{n = 1}^{4} 3^{n}\]
What do I do now?

Answer 2

How did you end up with \(3^n\)?

Answer 3

I think it should be
\[\frac{ 1 }{ 2 }\sum_{n = 1}^{4} 9^{n/2}\]

Answer 4

Since you just go from n=0 to 4, you can just calculate directly.

Answer 5

\[\frac{ 1 }{ 2 }\sum_{n = 1}^{4} 9^{n/2} = \dfrac{1}{2}(9^{0.5}+9^1+9^{1.5}+9^2)\]

Answer 6

ohh now I see how you have \(3^n\)

Answer 7

either way, just calculate directly.

Answer 8

thanks!!

Answer 9

silly my brain...

Welcome!