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OpenStudy (jaybear97):
I have to show all my work on this one
OpenStudy (anonymous):
Good, just trust yourself, you could've got that one
OpenStudy (anonymous):
do you know the pythagorean theorem
OpenStudy (jaybear97):
Not really...
OpenStudy (anonymous):
ok how about sine
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OpenStudy (anonymous):
pythagorean theorem is a^2+b^2=c^2
c is the hypotenuse
OpenStudy (jaybear97):
Thats what I thought it was but i was not sure!
OpenStudy (anonymous):
4^2+b^2=8^2
because you need to find the height
OpenStudy (anonymous):
64-16= b^2
OpenStudy (jaybear97):
48
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OpenStudy (anonymous):
yes now find the most radical form of the square root of 48
OpenStudy (jaybear97):
Isn't it 4 square root of 3
OpenStudy (anonymous):
yes, now you first need to find the area of one of the shapes you see 2 by the dotted lines. let's start with the triangle. 4 times 4 square root of 3 divided by 2 = area of your triangle
OpenStudy (jaybear97):
19.59?
OpenStudy (anonymous):
yes. now lets find the area of the rectangle.
6 times 4 square root of 3= area of rectangle
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OpenStudy (anonymous):
then add that to the area of your triangle, and you have got your answer
OpenStudy (jaybear97):
41.569
OpenStudy (anonymous):
yes but since it says, if it is not an integer leave it in the most radical form, your answer would be?
OpenStudy (anonymous):
it might help to go all the way back to the area of your triangle and see your radical form of that area, and add it to the radical form of the other area
OpenStudy (jaybear97):
41.7/
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OpenStudy (jaybear97):
i meant 41.6?
OpenStudy (anonymous):
yep
OpenStudy (anonymous):
that is what i got
OpenStudy (jaybear97):
I have to show my work so im not sure what to put
OpenStudy (anonymous):
just show what you did to find the area of the triangle, then the rectangle, then when you added them up together
just show the equations we used to find your answer
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