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Mathematics 11 Online
OpenStudy (anonymous):

Please help will fan and medal!

OpenStudy (anonymous):

OpenStudy (anonymous):

question ^

OpenStudy (anonymous):

plug in a and b and then just sum up.

OpenStudy (butterflydreamer):

all you need to do is sub in the values they've given to you :) So since a = 4, b = 3 sub it into: 6 + 4/a + b/3 So, 6 + 4/4 + 3/3 = ?

HanAkoSolo (jamierox4ev3r):

if you \(\Large\frac{4}{4}\) and \(\Large\frac{3}{3}\) then both of those are equivalent to 1 so you would have: 6+1+1

HanAkoSolo (jamierox4ev3r):

@coolman500 Please don't provide direct answers. It is against the rules here and does not help the user learn. Thank you :)

OpenStudy (anonymous):

there

HanAkoSolo (jamierox4ev3r):

okay...next time, make sure you provide the explanation first, and then an answer

OpenStudy (anonymous):

they did so I answered

HanAkoSolo (jamierox4ev3r):

@kira1502 do you understand how we solved this problem?

OpenStudy (anonymous):

lol shes not on

HanAkoSolo (jamierox4ev3r):

when plugging a=4 and b=3, the fractions turn into whole numbers. More specifically, they turn into 1. ;-; @starlord6200 i just realized

OpenStudy (anonymous):

\[6+\frac{ 4 }{ a }+ \frac{ b }{ 3 } \] where a =4 and b=3. Plug in 4 on a and 3 on b

OpenStudy (anonymous):

the dream died x_x

OpenStudy (anonymous):

it's 8 if you add it all up

HanAkoSolo (jamierox4ev3r):

c'mon @Mateaus , our work here is done *yanks out of question*

OpenStudy (anonymous):

none of us got a medal or fanned and she said she would

OpenStudy (anonymous):

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