Question

HELP PLEASE WILL GIVE MEDAL.
Matt forgot to put the fabric softener in the wash. As his socks tumbled in the dryer, they became charged. If a small piece of lint with a charge of +1.25 E -19 C is attracted to the socks by a force of 3.0 E -9 N, what is the magnitude of the electric field at this location?

Answer 1

http://www.physicsclassroom.com/class/estatics/Lesson-4/Electric-Field-Intensity

Answer 2

I got the equation

Answer 3

Ok, so, what do you think you should do with it?

Answer 4

Fe = (8.99E 9N *m^2/c^2) (1.5E -19C) (3.0E -9N)?

Answer 5

What equation are you looking at?

Answer 6

Fe = (Kq1q2)/d2

Answer 7

I think we should use:
Electric Field Strength=Force/Charge

Answer 8

so it would be 3.0 E -9 N,/+1.25 E -19C

Answer 9

Right.

Answer 10

so how would you solve for that
Do you do (3.0 x -9)/ ( 1.25 x -19)?

Answer 11

Well, (3.0x10^-9)/(1.25x10^-19)

Answer 12

ohh ok

Answer 13

i got like 20 billion

Answer 14

24 billion

Answer 15

Yeah, I got 2.4E10 N/C

Answer 16

ok

Answer 17

Suppose an electric field with a magnitude of 2.8 E 4 N/C at a certain location, points due south. If a charge of -4.0 E -6 C is brought to the location, what is the electrostatic force that acts on this charge?

Answer 18

Would this be the same equation

Answer 19

Yep.

Answer 20

OK and

Answer 21

Think back to Coulomb's Law. Two coins with identical charges are placed on a lab table 1.35 m apart.
A.)If each coin experiences a force of 2.0 N because of the presence of the other coin, calculate the charge on each coin.
B.)Would the force be classified as a force of attraction or repulsion? Explain your answer.

Answer 22

Wait, what did you get the total answer for the last one to be?

Answer 23

i havent done it yet im in a rush and need to go to a dentist appointment

Answer 24

Ok, might want to finish when you get back then.

Answer 25

ill send you a message thanks you

Answer 26

Ok, you're welcome. :-)

Answer 27

Ok im back

Answer 28

Ok, so, did you finish the electric field one?

Answer 29

not yet

Answer 30

Electric Field Strength= Force/Charge
(2.8E x 10^4) (-4.0 x 10 ^ -6)

Answer 31

Hm, how do you plug those numbers in?

Answer 32

Electric field strength=3E-9/(1.25E-19)=?

Answer 33

24 billion
2.4E 10 N/C

Answer 34

correct?

Answer 35

Correct!!!!!!!

Answer 36

This whole issue you had could have easily been avoided if Matt had just put the soap in the washer.