Help with vectors
Which of the following is a vector that has a direction angle of θ = 77° and a magnitude of 4/7 ? Round your answer to the nearest tenth.
tan(77)=4.33147587
|dw:1430761726642:dw|
(0.1, -0.6) (0.6, 0.1) (0.1, 0.6) (-0.6, 0.1)
this means that both points have to be positive
so that eliminates a and d
actually you would have to find the magnitude then multiply it by cos77 to find x and sin77 to find y
hint: |dw:1430761943436:dw| we have to request that: \[\arctan \left( {\frac{y}{x}} \right) = 77^\circ \]
@Michele_Laino The closest I got to was 80 and that was arcsin(.6/.1)
I know it, I have computed that before
what am i doing wrong :/
if we consider the other case we have: \[\theta = \arctan \left( {1/6} \right) \ne 77^\circ \]
That is true, but we are dealing with .1 and .6 :s
@amistre64
The answer is .1, .6 because 4/7cos77 and 4/7sin77
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