Question

Solve 3x2 - 12x + 2 = 0 by using a method different from the one you used in Part B. Show the steps of your work can you solve using quadratic formula please!! @TuringTest @dan815 @nincompoop

Answer 1

@amistre64 @ganeshie8

Answer 2

@Michele_Laino

Answer 3

referring to a generic quadratic equation:
a*x^2+b*x+c=0, the roots, are given by the subsequent formula (quadratic formula):
\[\Large x = \frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}\]

Answer 4

okay.

Answer 5

now in our case , we have:
a=3, b=-12, c=2

Answer 6

okayy

Answer 7

and the roots are:
\[\Large \begin{gathered}
x = \frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}} = \hfill \\
\hfill \\
= \frac{{12 \pm \sqrt {{{12}^2} - 4 \times 3 \times 2} }}{{2 \times 3}} = ... = \hfill \\
\end{gathered} \]

Answer 8

so i solve that

Answer 9

i got 16?

Answer 10

12+-square root 144-24/6

Answer 11

I got this:
\[\Large \begin{gathered}
\frac{{12 \pm \sqrt {{{12}^2} - 4 \times 3 \times 2} }}{{2 \times 3}} = \frac{{12 \pm \sqrt {144 - 24} }}{6} = \hfill \\
\hfill \\
= \frac{{12 \pm \sqrt {120} }}{6} = \frac{{12 \pm 2\sqrt {30} }}{6} = \frac{{6 \pm \sqrt {30} }}{3} \hfill \\
\end{gathered} \]

Answer 12

holy thats confusing

Answer 13

we can write this:
\[\sqrt {120} = \sqrt {4 \times 30} = \sqrt {{2^2} \times 30} = 2\sqrt {30} \]

Answer 14

so what would be my answer lol im confused xD?

Answer 15

more explanation:
\[\frac{{12 \pm \sqrt {120} }}{6} = \frac{{12 \pm 2\sqrt {30} }}{6} = \frac{{2\left( {6 \pm \sqrt {30} } \right)}}{6} = \frac{{6 \pm \sqrt {30} }}{3}\]
the roots of your equation are:
\[{x_1} = \frac{{6 + \sqrt {30} }}{3},\quad {x_2} = \frac{{6 - \sqrt {30} }}{3}\]

Answer 16

thats my answer correcT?

Answer 17

yes! nevertheless you have to simplify the expression that you have got

Answer 18

Okay! can you help me on one more question?

Answer 19

yes! please wait, someone is calling me to my phone