Question

2) WILL GIVE MEDAL AND FAN!!

Which of the following is not a perfect square trinomial?

a. 169 – 26y + y2

b. 81 + 18y + y2

c. 64 + 8y + y2

d. 25 + 10y + y2

Answer 1

which one do u think

Answer 2

im not usre at all! @israa88

Answer 3

i would go with A

Answer 4

ALL PSTs look like this: \((a+b)^{2} = a^{2} + 2ab + b^{2}\) -- ALL of them.

User the first and last term to predict the middle term

Answer 5

so maybe A? @tkhunny

Answer 6

Maybe. Did you test it? See if it fits the form.

Answer 7

ya I think it is A... @tkhunny

Answer 8

you are right :)

Answer 9

You're guessing.

Provide the square roots

\(\sqrt{169} = \)

\(\sqrt{81} = \)

\(\sqrt{64} = \)

\(\sqrt{25} = \)

Answer 10

ok @tkhunny then what next ...

Answer 11

You didn't provide the square roots. What are they?

Answer 12

israa88 is also just guessing.

Answer 13

lol @tkhunny honestly anyone can answer that question but that doesn't proof that they are guessing or not

Answer 14

I didn't say it did. I did say that you are guessing.

Answer 15

Now, where are those square roots?

Answer 16

i am not guessing the answer to ur questions is 13, 9, 8 , and 5

Answer 17

i am not guessing now am i

Answer 18

Sadly, now we don't know if brae could have done that.

@brae You still have shown no work. Multiply those square roots by 2. What do you get?

Answer 19

me or him ?

Answer 20

Who posted the question? @brae Are you still here? We're almost done.

Answer 21

Well exactly Sir you can't come and say i am guessing as well because I really wasn't so have a wonderful day sir and next time plz dont judge :)

Answer 22

umm this is kinda hard...

Answer 23

You're still guessing.

Remember the form: \((a+b)^{2} = a^{2} + 2ab = b^{2}\)

Constant terms: 169 81 64 25 -- These are the '\(b^{2}\)'s in the form.
Square roots: 13 9 8 5 -- These are the '\(b\)'s in the form.
Multiply by 2: 26 18 16 10 -- These represent "\(2b\)"

Look at the coefficients on the middle terms. Did we hit them or not?