Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

Since people aren't helping me in the chemistry section, mathematics is my second best choice to post this... What mass of KCl would be needed to form a saturated solution if the KCl was dissolved in 200 g of water at 80 °C?

OpenStudy (anonymous):

I need help... Really. I need to get this done

OpenStudy (amistre64):

its best to post it in chem, and then come to math chat with a link to your question to draw people to it. not sure how mathy an approach would be unless you know some formulas or properties related to this

OpenStudy (amistre64):

saturation is the point where no more is dissolved .... but other than that i got nothing

OpenStudy (anonymous):

Look buddy... no one is noticing my question on the chemistry page and I need help...

OpenStudy (amistre64):

im not your buddy .... im a moderator of this site. unless you know of a mathy approach to this then keep it where it belongs.

OpenStudy (amistre64):

do you know any dissolution formula?

OpenStudy (anonymous):

??? Okay.... This has math in it...js

OpenStudy (anonymous):

What is that?

OpenStudy (amistre64):

i cant find anything i can actually read and understand about this on google. something about Ksp or aqueous stuff ... sorry, its greek to me.

OpenStudy (anonymous):

Uggghh.... I guess I'll just take it down. This really sucks cause I need help with this..

OpenStudy (amistre64):

yeah, i cant make sense of any of it from the google .... any approach i try to think of would just be a wild guess. good luck tho

OpenStudy (sdfgsdfgs):

Look for KCl in the water solubility table on wikipedia here: http://en.wikipedia.org/wiki/Solubility_table#P find the solubility for 80deg. the solubility is given in g/kg i.e. ___ g of KCl in 1 kg of H2O. then solve for ur ans. good luck!

OpenStudy (anonymous):

Oh thank you !!!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!