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OpenStudy (anonymous):
are you talking about the 9/x^2 or the 9?
jimthompson5910 (jim_thompson5910):
yes 9/x^2
OpenStudy (anonymous):
ok
jimthompson5910 (jim_thompson5910):
\[\Large f \ ' (x) = \frac{9}{x^2}\]
\[\Large f \ ' (6) = \ ??\]
OpenStudy (anonymous):
sorry i lost connection i'm back now! was it 9/36??
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OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
yes, now reduce
OpenStudy (anonymous):
1/4?
jimthompson5910 (jim_thompson5910):
yep
OpenStudy (anonymous):
yay! i have one more, can you help me?
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jimthompson5910 (jim_thompson5910):
sure
OpenStudy (anonymous):
its a short response question;
The position of an object at time t is given by s(t) = -8 - 9t. Find the instantaneous velocity at t = 1 by finding the derivative.
jimthompson5910 (jim_thompson5910):
you can use wolfram alpha to compute the derivative function
jimthompson5910 (jim_thompson5910):
it's unfair how they are asking you derivative questions in a pre-calc class
OpenStudy (anonymous):
i'm in the last chapter so idk
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jimthompson5910 (jim_thompson5910):
what is s ' (t) ?
OpenStudy (anonymous):
to be completely honest i don't know...
jimthompson5910 (jim_thompson5910):
what do you get when you type in "derivative of s(t) = -8 - 9t" into wolfram
OpenStudy (anonymous):
-9 :)
jimthompson5910 (jim_thompson5910):
yep, in this case the derivative is the same no matter what t is
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jimthompson5910 (jim_thompson5910):
basically the rate of change is the same throughout
OpenStudy (anonymous):
alright so to get credit for the short essay what else do i need to put??
jimthompson5910 (jim_thompson5910):
you can throw in how it's a linear equation which has the same slope throughout
jimthompson5910 (jim_thompson5910):
slope of linear equation = rate of change
OpenStudy (anonymous):
it's a linear equation so the rate or change remains the same, which is -9??
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OpenStudy (anonymous):
how does that sound?
jimthompson5910 (jim_thompson5910):
that sounds good
jimthompson5910 (jim_thompson5910):
oh it's "rate OF change" not rate or change
OpenStudy (anonymous):
okay thanks!! :D You've been a great help!!!
jimthompson5910 (jim_thompson5910):
np
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