Is this differentiable and continuous?

Question

loser66 · Answer

What is it?

anonymous · Answer

opps I will attach it now

anonymous · Answer

attachment

anonymous · Answer

this is an online solution; I just don't get how the person got the graph? @Loser66

anonymous · Answer

(this is non-calculator)

loser66 · Answer

You are correct. It's A, to me

anonymous · Answer

how did you do it? did you have to draw a graph first?

loser66 · Answer

you have the whole table. Do you understand it?

anonymous · Answer

no; I don't get how you would know that it's concave down 2 halves like that? Like I could have drawn a parabola with those table values, which would make it differentible

loser66 · Answer

for x =-2, then x-2 = -2-2=-4, then take absolute value |-4|=4, then take square root =2, ok?

rainbow_rocks03 · Answer

@shirley128 just look at the defintions on google and also just look up the difference between those words you didn't have to ask on here.

anonymous · Answer

Just imagine the tangent lines.

anonymous · Answer

@rainbow_rocks03 lol I'm not asking the definitions; sorry the image of the question is attached 
@wio I don't get it...?

rainbow_rocks03 · Answer

oh lol never mind :) hope you get the answer

rainbow_rocks03 · Answer

but people plz no direct answers

rainbow_rocks03 · Answer

just saying

rainbow_rocks03 · Answer

just saying

anonymous · Answer

Consider $g(x) = |x-2|$ and $h(x) = \sqrt x$.  
So we have $f(x) = h(g(x))$ and the derivative is: $$
f'(x) = h'(g(x))g'(x)
$$

anonymous · Answer

Wait, maybe you don't know how to do derivatives yet?

anonymous · Answer

@wio yup I'm following that, and then?