Consider a set of 7500 scores on a national test whose score is known to be distributed normally with a mean of 510 and a standard deviation of 85. About how many scores greater than 600 would we expect to find? A. 3750 B. 2664 C. 6414 D. 575 E. 1086
@perl i did 6899/7500 since before you said find the probability of choosing a score greater than 600 but I'm not sure what to do next
P( X > 600) = P( Z > ? )
first lets change the raw score of 600 to a z score
the z score tells you how many standard deviations away you are from the mean . so how many standard deviations away from the mean is the score of 600 ?
600-510/x= 7500 90/x=7500 x= 83.3
i think i did something wrong finding x
z = (600 - 510) / 85 will give you the z score
oh sorry thanks, ok so 90/85=1.05882
so we want P( Z > 1.0588)
i looked it up on the table and got around .8554
the table gave you the value for P( Z < 1.0588) , so we need to subtract that from 1 to get P( Z > 1.0588)
ok so i got 1-.8554=.1446
correct
now multiply that probability by 7500 , to get how many you expect to score more than 600
ok when i did that i got 1084.5 which is close to one of my answers 1086
thanks!(:
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