find the solution to the system of equations by using either graphing or substitution. y = 6 - x and y = x -2 a. (2,4) b. (-4,2) c. (4,2) d. no solutions
so put 1 of the equations as y
or like this 6-z=z-2
then solve / simplify
ok so it would be the first one?
maybe
\(\large\color{black}{ \displaystyle y = 6 - x }\) \(\large\color{black}{ \displaystyle y = x -2 }\) the first equation tells you that y is the same thing as 6-x, so you can replace the y in the second equation by 6-x. your first equation \(\large\color{red}{ \displaystyle y = 6 - x }\) your second equation \(\large\color{black}{ \displaystyle y = x -2 }\) replace the y with 6-x in the second equation \(\large\color{black}{ \displaystyle 6-x = x -2 }\) (this is a substitution)
yep yep
thanks @SolomonZelman
<3
do you get the substitution method in this case, @120hoho, or not ?
he said he thinks its the 1st one
i doubt that the first answer is correct..... lets solve the problem and lets know for sure, okay?
@SolomonZelman u got this right cuz i gtg
Hoho, did you understand the substitution method that I explained?
yeah
ok, so at this point we have: \(\large\color{black}{ \displaystyle 6-x = x -2 }\)
you need to {solve for/ isolate the} x.
lets add x to both sides. your equation right now: \(\large\color{black}{ \displaystyle 6-x = x -2 }\) adding x to both sides (as shown in blue) \(\large\color{black}{ \displaystyle 6-x \color{blue}{+x} = x -2\color{blue}{+x} }\)
then tell me what is going to happen (what you get) on each side
double x's
more precisely please. What do you get on the right side? What do you get on the left side?
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