please help me
find particular integral of d2u/dx2 + u = cos (x-xo)

Question

please help me
find particular integral of d2u/dx2 + u = cos (x-xo)

solomonzelman · Answer

what I see so far is:      $\large\color{black}{ \displaystyle \frac{ {\rm d}^2u}{ {\rm d}x^2}+u=\cos\left(x-x_0\right)  }$

anonymous · Answer

yes it is my que

anonymous · Answer

answer please

anonymous · Answer

how u find up
what method is used...the ans that i have is (x-xo)/2 sin(x-xo)

unklerhaukus · Answer

Have you found the homogenous solution?

anonymous · Answer

no,i want to find in homogeneous solution

unklerhaukus · Answer

The homogenous solution solves 

$$u''+u=0$$

nikvist · Answer

attachment

anonymous · Answer

ok if i ask u to solve up for d2u/dx2+u =exp(i(x-xo))
where i+iota

unklerhaukus · Answer

Variation of parameters?

anonymous · Answer

means?

unklerhaukus · Answer

Variation of Parameters, is one method to find the particular integral. But if you haven't learnt it, there are other methods.

anonymous · Answer

ok solve it by any method....but ans should be (x-xo)/2 cos(x-xo)+i sin(x-xo)