Question

please help me
find particular integral of d2u/dx2 + u = cos (x-xo)

Answer 1

what I see so far is: \(\large\color{black}{ \displaystyle \frac{ {\rm d}^2u}{ {\rm d}x^2}+u=\cos\left(x-x_0\right) }\)

Answer 2

yes it is my que

Answer 3

answer please

Answer 4

how u find up
what method is used...the ans that i have is (x-xo)/2 sin(x-xo)

Answer 5

Have you found the homogenous solution?

Answer 6

no,i want to find in homogeneous solution

Answer 7

The homogenous solution solves

\[u''+u=0\]

Answer 8

ok if i ask u to solve up for d2u/dx2+u =exp(i(x-xo))
where i+iota

Answer 9

Variation of parameters?

Answer 10

means?

Answer 11

Variation of Parameters, is one method to find the particular integral. But if you haven't learnt it, there are other methods.

Answer 12

ok solve it by any method....but ans should be (x-xo)/2 cos(x-xo)+i sin(x-xo)