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Carbon-14 forms nitrogen-14 by A. alpha decay. B. beta decay. C. gamma decay. D. none of the above
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hint: here is the decay reaction: \[\Large {}_6^{14}C \to {}_7^{14}N + {}_{ - 1}^0e\]
"e" stands for electron
I have no clue what the answer is
hint: the rays composed by electrons, are called negative beta rays
\[ _{\ \ 6}^{14}\textrm C^{~}_8 \longrightarrow {}_{\ \ 7}^{14}\textrm N_7^+ +\overbrace{ {}_{ - 1}^{\ \ \ 0}e_0^-}^{\displaystyle\beta^-}+\bar\nu_e\]
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