Prove that the function "the sign of x" y=sgnx,such that sgnx={1 for x>0 {0 for x=0 {-1 for x<0 has no limit at the point where x=0.
Can you help me please? @amistre64 @Michele_Laino
what defines a limit?
the lim f(x) as x approaches to 0
not quite, its more precise than that
if something is there, then we should be able to get there no matter which direction we come from. if we reach the same place fro any direction, then the limit is the place that everything converges to.
i guess *as x approaches to 0
since we are limited by the direction of x, we have 2 ways to approach f(a) at a
what is the limit as x approaches 0 from the left? from the right? is it the same?
what is lim f(0) as x approaches from the left? f(-1), f(-.5), f(-.25), f(-.0025), .... -------------------------- what is lim f(0) as x approaches from the right? f(1), f(.5), f(.25), f(.0025), .... --------------------------- do lims of f(0) match from the left and from the right?
I didn't get it ! @amistre64
"Prove" suggests you have to use the \(\epsilon-\delta\) definition, but that depends on whether @M_lowreen has learned about that.
what's that ? @SithsAndGiggles
what are the values for: f(-1), f(-.5), f(-.25), f(-.0025)? what are the values for: f(1), f(.5), f(.25), f(.0025)?
@M_lowreen it's the rigorous way of proving that a limit exists. If you haven't learned it yet, don't worry about it.
graphing the function might help ... and knowing how your material defines this limiting process would be good.
we r given that sgnx=1for x>0 , sgnx=0 for x=0 and sgnx=-1 for x<0 that's all we know , how can i graph it !? @amistre64
by following the definition how do you graph something like f(x) = x?
start with the xy axises ... and where x is < 0 draw the line y=-1 where x is > 0 draw the line y= where x is = 0 make a point at y=0
we give some values to the x and find f(x) ... but we have not f(x)=... it's sgnx=
|dw:1430849785884:dw|
f(x) is a name, a generic name sgn(x) is a name, a specific name
you simply draw out the rule that defines it
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