Question

A container holds 50 electronic components, of which 10 are defective.
If 6 components are drawn at random from the container, the probability that at least 4 are not defective is ? If 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is ?

Answer 1

what are you are answer choices

Answer 2

question 1 choices
0.26
0.42
0.75
0.91
1.00

Answer 3

question 2 choices
0.147
0.203
0.300
0.375
0.750

Answer 4

hmm this is a lot harder than the other questions so give me a sec, for question i know it is not the last or first options

Answer 5

for question 1*

Answer 6

hmm this just an educated guess but i think it is .91 here is my explanation...

Answer 7

the chance of drawing a undefected device of one roll are 4/5 (40/50) = .8

Answer 8

but now we are not asking for 40 we just want at least four, so the chances are not 100% but it is much higher than 75

Answer 9

leaving only 91

Answer 10

sadly working it out i stubled, but for number one you just need to look at it logically

Answer 11

i am 91% sure it is the right anwer :)

Answer 12

but realstically i would go with 91

Answer 13

now onto question two

Answer 14

instead of working it out let me look at it logically

Answer 15

so we have 10 defective devices out of 50

Answer 16

just drawing one is a 1/5 (q0/50) chance

Answer 17

10*

Answer 18

wich is equal to .2

Answer 19

unlike the last question, the odds are not in our favor

Answer 20

meaning it is lower than .2

Answer 21

leaving only one possible answer

Answer 22

A

Answer 23

even if it were only asking one defective device and not 3 the chances would not be greater than .2 so b + the other choices are impossible

Answer 24

for one*

Answer 25

did i make sense :)

Answer 26

yea thanks

Answer 27

no problem :)