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Chemistry 6 Online
OpenStudy (anonymous):

A food scientist reacted 34g of ammonia with 3g of hydrogen chloride. Calculate the maximum mass of ammonium chloride the food scientist could produce

OpenStudy (anonymous):

@Somy

OpenStudy (somy):

write the reaction first and balance it

OpenStudy (anonymous):

ok ammonia +hydrogen chloride=ammonium chloride @Somy

OpenStudy (anonymous):

next.. @Somy

OpenStudy (somy):

with their letter codes and balance it

OpenStudy (anonymous):

we dont need to do that the instructions say write the word equation

OpenStudy (anonymous):

do you know the solution to this problem if not I will ask somebody else for help :) @Somy

OpenStudy (somy):

i do know but i need u to follow what i say.. i want u to write it in the letter format so u can see the ratio clearly

OpenStudy (somy):

well if word format is good for you then go with it use the mass of each you can find their molecular mass from periodic table find mole

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

the mass of hydrogen is 1 and the mass of ammonia is 17

OpenStudy (somy):

yep that is molecular mass now do u know the mole formula?

OpenStudy (anonymous):

mass in g dividied by mr of element

OpenStudy (anonymous):

@Somy

OpenStudy (somy):

yep so do it

OpenStudy (anonymous):

the mass of ammonia divided by mr of hydrogen or other way round i am confused

OpenStudy (somy):

no look you are given mass of ammonia so use the mass and ITS OWN molecular mass

OpenStudy (somy):

to find its own mole

OpenStudy (somy):

then do same thing with HCl

OpenStudy (anonymous):

im confused @Somy

OpenStudy (anonymous):

how will the format of the method look like

OpenStudy (somy):

A food scientist reacted 34g of ammonia with 3g of hydrogen chloride. Calculate the maximum mass of ammonium chloride the food scientist could produce NH3 + HCl -> NH4Cl 34g 3g you are given 34g of NH3 you said molecular mass of NH3 is 17, so now you have mass and molecular mass of NH3 now you can find mole of NH3 mole = mass / molecular mass = 34 / 17 = ........moles of NH3

OpenStudy (anonymous):

its okay I asked a chemist and he helped me how to do it @somy

OpenStudy (somy):

okay :)

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