Lisa invests $4,000 in two types of bonds, bond A and bond B. Bond A offers a 10% return, and bond B offers a 6% return. Lisa invests $x in bond A and $y in bond B. Her total return on the investment is $340.
The system of linear equations defining the situation is x+y=4,000 and .1x=.06y=340. The amount Lisa invested at the rate of 10% is ___ , and the amount she invested at the rate of 6% is ___ .

Question

Lisa invests $4,000 in two types of bonds, bond A and bond B. Bond A offers a 10% return, and bond B offers a 6% return. Lisa invests $x in bond A and $y in bond B. Her total return on the investment is $340.
The system of linear equations defining the situation is x+y=4,000 and .1x=.06y=340. The amount Lisa invested at the rate of 10% is ___ , and the amount she invested at the rate of 6% is ___ .

anonymous · Answer

I think I got the linear equation right, Now how do I find how much she invested on each at 10% and 6%

anonymous · Answer

@amistre64

anonymous · Answer

@Hero

amistre64 · Answer

Lisa invests $4,000 in two types of bonds, bond A and bond B. 

A + B = 4000


Bond A offers a 10% return, and bond B offers a 6% return. 

.10 A + .06 B = 340

Her total return on the investment is $340.

solve the system of equations with whatever method strikes your fancy

amistre64 · Answer

since the relationship A+B=4000 must satisfy the setup for all values A and B

we can state that A = 2000 + n, and B = 2000 -n

afterall:  2000 +n + 2000 - n = 4000 for all n

.10(2000+n) + .06(2000-n) = 340,  once we know n we know A and B

anonymous · Answer

I figured it out I forgot to close, I think it was 1500 for b or 2500 for a (: Thanks though