Question

Find the solution of this system of equations algebraically.
(A) y = -x
(B) y = x3 + 3x2 + 2x
(0, 0)
(0, -1) and (0, -2)
(0, 0), (-1, 1) and (-2, 2)
(-1, 1) and (-3, 3)
It has no solution.

Answer 1

I get 0,-1,-2 for the x values

Answer 2

@freckles

Answer 3

hey

Answer 4

hey

Answer 5

did you replace y in the equation with -x

that is did you solve:
\[-x=x^3+3x^2+2x\]

Answer 6

I got x to equal 0 on the equation you just put

Answer 7

you add x on both sides
\[0=x^3+3x^2+3x \\0=x(x^2+3x+3)\]
and yes one solution is x=0
but what happens when you solve x^2+3x+3=0?

Answer 8

I get 0 still

Answer 9

well yes the only real solution you get from the equation 0=x(x^2+3x+3) is zero
because x^2+3x+3=0 gives you complex solutions

Answer 10

so the answer is a?

Answer 11

so (0,0) is the only point of intersection