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Mathematics 4 Online
OpenStudy (anonymous):

The position of an object at time t is given by s(t) = -2 - 6t. Find the instantaneous velocity at t = 2 by finding the derivative

OpenStudy (anonymous):

The question tells you exactly what to do. Do you know how to take the derivative? The derivative of position is velocity. That is, d[s(t)]/dt = v(t). Now plug in t=2, into v(t).

OpenStudy (anonymous):

-2-12?

OpenStudy (anonymous):

is the answer -14??

OpenStudy (anonymous):

@TurtleMuffin

OpenStudy (anonymous):

You plugged t=2 into s(t). Take the derivative first. They're asking for velocity.

OpenStudy (anonymous):

i dont remember how to do that

OpenStudy (anonymous):

Velocity is rate of change. What's the rate of change of s(t)?

OpenStudy (anonymous):

How fast does the position, s(t), change with respect to time, t?

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